0%

小猫爬山

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
#include <cstdio>
#include <algorithm>
using namespace std;

const int MAXN = 20;

int n, w, cats[MAXN], f[MAXN], ans;
bool book[MAXN];

void dfs(int ind = 1 /*当前猫的序号*/, int sum = 0 /*当前已用缆车数*/) {
if(sum > ans) return; //超过当前最大缆车数量,直接退出
if(ind == n + 1) { //所有猫全部坐上车,且缆车数量不大于当前最大缆车数量,保存并退出
if(sum < ans) ans = sum;
return;
}
for(int i = 1; i <= sum; i ++) {
if(cats[ind] + f[i] <= w) {
f[i] += cats[ind];
dfs(ind + 1, sum);
f[i] -= cats[ind];
}
}
f[sum + 1] = cats[ind];
dfs(ind + 1, sum + 1);
f[sum + 1] = 0;
}

bool cmp(int x, int y) {
return x > y;
}

int main() {
scanf("%d %d ", &n, &w);
for(int i = 1; i <= n ; i ++) {
scanf("%d", &cats[i]);
}
ans = n;
sort(cats + 1, cats + 1 + n, cmp);
dfs();
printf("%d", ans);
return 0;
}

欢迎关注我的其它发布渠道